36x^2+72x=288

Solution for 36x^2+72x=288 equation:

36x^2+72x=288

We move all terms to the left:

36x^2+72x-(288)=0

a = 36; b = 72; c = -288;
Δ = b2-4ac
Δ = 722-4·36·(-288)
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{46656}=216$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-216}{2*36}=\frac{-288}{72}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+216}{2*36}=\frac{144}{72}
=2
$